10c^2+14c-12=0

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Solution for 10c^2+14c-12=0 equation: 



10c^2+14c-12=0

a = 10; b = 14; c = -12;
Δ = b2-4ac
Δ = 142-4·10·(-12)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$


$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-26}{2*10}=\frac{-40}{20}
=-2
$


$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+26}{2*10}=\frac{12}{20}
=3/5
$

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